-3u^2+60u=147

Solution for -3u^2+60u=147 equation:

-3u^2+60u=147

We move all terms to the left:

-3u^2+60u-(147)=0

a = -3; b = 60; c = -147;
Δ = b2-4ac
Δ = 602-4·(-3)·(-147)
Δ = 1836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1836}=\sqrt{36*51}=\sqrt{36}*\sqrt{51}=6\sqrt{51}$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-6\sqrt{51}}{2*-3}=\frac{-60-6\sqrt{51}}{-6}
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+6\sqrt{51}}{2*-3}=\frac{-60+6\sqrt{51}}{-6}
$